Forum
14:27
29/06/2014
hi everyone, i'm new to using jqgrid and and actually have a probleme that i need your help. i'm trying to set a grid with a number of column depend on the result of the query. more clearly, my query return a result such like that: 3 column: competency, name, level. i want to display "competency" as a left frozen column and "name" as rows headers. for example:
competency  Peter     Phillip      Max
architect       beginner  expert     beginner
IT              expert      beginner  expert
it's should be simple for you but i have tried to do this since the last two day with any success. i'm using jqgrid 4.6.
Thank you very much for your help.
11:56
Moderators
30/10/2007
Hello,
Currently we do not support this.
You should generate the colModel Dynamically and then put the data depending on this colModel.
It is not so simple as you say - it is a very difficult to do.
Kind Regards
For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.
Most Users Ever Online: 715
Currently Online:
32 Guest(s)
Currently Browsing this Page:
1 Guest(s)
Top Posters:
OlegK: 1255
markw65: 179
kobruleht: 144
phicarre: 132
YamilBracho: 124
Renso: 118
Member Stats:
Guest Posters: 447
Members: 11373
Moderators: 2
Admins: 1
Forum Stats:
Groups: 1
Forums: 8
Topics: 10592
Posts: 31289
Newest Members:
, razia, Prankie, psky, praveen neelam, greg.valainis@pa-tech.comModerators: tony: 7721, Rumen[Trirand]: 81
Administrators: admin: 66