Forum
20:52
28/07/2013
I create a jqGrid using following code:
$("#MyGrid").jqGrid({
url: 'mycfc.cfc?method=MyMethod'+jQuery("#txtCaseNumber").val()})
to create a jqGrid and would like topass parameter to the jqGrid at run time, because I want to show details informaiton base on user input.
Above code works only I have value in the txtCaseNumber control.
Your help and information is great appreciated,
Regards,
Iccsi,
17:33
Moderators
30/10/2007
Hello,
Not sure I understand the problem.
Try to create a variable and pass the variable and not the actuall value.
Regards
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