jQuery Grid Plugin - jqGridForum

Topic RSS

jqGrid AJAX Question

23/10/2009
14:16

geezimgood

New Member

Members

Forum Posts: 1

Member Since:
23/10/2009

Offline

Hey all,

I'm wondering if it is possible for jqGrid to return the currently visible columns and current column order (perhaps in a JSON string). Is there a built in method that I can use to do this (e.g. once a user removes a column from the grid, can I get that "state")?

The reason why I want to get this information is because I would like to be able to allow a user to "save" their current view after they add / remove / sort records on the grid.

Thanks Cool

27/10/2009
02:16

tony

Sofia, Bulgaria

Moderator

Members

Moderators

Forum Posts: 7721

Member Since:
30/10/2007

Offline

Hello,

jqGrid have methods and events to allmost what you want. No rady solutions

So in your case:

var mycolModel = $("#mygrid").getGridParam("colModel");

$.each(mycolModel, function (i) {

if(this.hidden ) { // we check if the column is hidden

// do something

}

// this.name - will give you the name and i variable the order

});

Regards

Tony

For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.

All RSS

Forum Timezone: Europe/Sofia

Most Users Ever Online: 715

Currently Online:
52 Guest(s)

Currently Browsing this Page:
1 Guest(s)

Top Posters:

OlegK: 1255

markw65: 179

kobruleht: 144

phicarre: 132

YamilBracho: 124

Renso: 118

Member Stats:

Guest Posters: 447

Members: 11373

Moderators: 2

Admins: 1

Forum Stats:

Groups: 1

Forums: 8

Topics: 10592

Posts: 31289

Newest Members:

, razia, Prankie, psky, praveen neelam, greg.valainis@pa-tech.com

Moderators: tony: 7721, Rumen[Trirand]: 81

Administrators: admin: 66