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04:30

29/12/2009

example :
$a ="<a href='http://google.com'>goo...../a>";
while($row = mysql_fetch_array($result,MYSQL_ASSOC)) {
$s .= "<row id='". $row[id_komponen]."'>";
$s .= "<cell>". $i."</cell>";
$s .= "<cell>". $row[id_komponen]."</cell>";
$s .= "<cell>". $row[id_kategori]."</cell>";
$s .= "<cell>". $row[komponen]."</cell>";
$s .= "<cell>". $row[desk_komponen]."</cell>";
$s .= "<cell>". $row[nm_grup]."</cell>";
$s .= "<cell>". ' $a'."</cell>";
$s .= "<cell><![CDATA[". $row[poin]."]]></cell>";
$s .= "</row>";
$i++;}
$s .= "</rows>";
, i want to show the $a variable, as link.. can you gimme a solution, or this jq cannot be display as link? please, iam newbie
16:23

Moderators
30/10/2007

Hello,
Enclose your link in CDATA like the last cell.
instead of
$s .= “<cell>”. ' $a'.”</cell>”;
do
$s .= "<cell><![CDATA[".$a."]]></cell>";
Best Regards
Tony
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