Forum
Log In
Home
Topic RSS
08:47
09/11/2008
Offline
Hi,
I installed the last Version of jQGrid,
I wrote an example html, and an example.php.
The grid displays fine, but my example.php is never called
Example.php works fine if i call it directly from the browser (produces a json string)
the java script for jquery reacts correctly if i modifiy some parameters.
imagpath: 'themes/sand/images' produces a java console error
i tried many combination with url: .... (example.php is in the same directory than example.html'. I checked all the includes. No way to get example.php to run.
Any Ideas ?
Thanks
07:19
Moderators
30/10/2007
Offline
Hello,
Use FireBug console to see from where is called example.php.
Regards
Tony
For professional UI suites for Java Script and PHP visit us at our commercial products site - guriddo.net - by the very same guys that created jqGrid.
08:21
09/11/2008
Offline
Problem Solved :
Firefox was blocking the request
in a new tab, select url "about.config"
select the line : extensions.firefox.console.allowDoublePost.. set it true.
Other bug detected in my own code : don't use "echo" or "print" in the PHP program. it destroys the structure of json string awaited by jqgrid.
09:47
13/11/2008
Offline
Mike said:
…
Other bug detected in my own code : don’t use “echo†or “print†in the PHP program. it destroys the structure of json string awaited by jqgrid.
Best solution here is to create the desired array and then return the result of json_encode($dataarray).
Cheers,
P.
Most Users Ever Online: 715
Currently Online:
58 Guest(s)
Currently Browsing this Page:
1 Guest(s)
Top Posters:
OlegK: 1255
markw65: 179
kobruleht: 144
phicarre: 132
YamilBracho: 124
Renso: 118
Member Stats:
Guest Posters: 447
Members: 11373
Moderators: 2
Admins: 1
Forum Stats:
Groups: 1
Forums: 8
Topics: 10592
Posts: 31289
Newest Members:
, razia, Prankie, psky, praveen neelam, greg.valainis@pa-tech.comModerators: tony: 7721, Rumen[Trirand]: 81
Administrators: admin: 66
